y^2+(1/y)=333+(1/333)

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Solution for y^2+(1/y)=333+(1/333) equation: 



y^2+(1/y)=333+(1/333)

We move all terms to the left:

y^2+(1/y)-(333+(1/333))=0



Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

y^2+(+1/y)-(333+(+1/333))=0

We get rid of parentheses

y^2+1/y-(333+(+1/333))=0

We calculate fractions


y^2+()/333y^2+(-(333+(+1*y)/333y^2=0

We add all the numbers together, and all the variables

y^2+()/333y^2+(-(333+(+y)/333y^2=0

We multiply all the terms by the denominator


y^2*333y^2+(-(333+(+y)+()=0



We calculate terms in parentheses: +(-(333+(+y)+(), so:

-(333+(+y)+(



Wy multiply elements

333y^4+(-(333+(+y)+()=0



We calculate terms in parentheses: +(-(333+(+y)+(), so:

-(333+(+y)+(



We do not support eypression: y^4

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